Telangana Education News

Telangana Mein 65 Junior Colleges Ke Fire Safety Certificates Farzi Hone Ka Inkishaf

Location: Hyderabad, Telangana | Date: 26 October 2026

Telangana mein Intermediate taleem ke idaron se mutalliq ek aham mamla saamne aaya hai. Reports ke mutabiq, Telangana Board of Intermediate Education (TGBIE) ki jaanch mein 65 junior colleges ke fire safety certificates mein gadbad saamne aayi. Is mamle ne colleges mein fire safety ke intizamaat aur talaba ki hifazat par sawalat khade kar diye hain.

65 Junior colleges ke fire safety certificates mein gadbad ki report

3,241 Academic year 2026–27 ke liye manzoor-shuda colleges ki report

27 Zero admissions ki darkhwast dene wale colleges

₹4 Crore+ Corporate colleges par jurmane ki report

65 Junior Colleges Ke Fire Safety NOCs Par Sawal

Reports ke mutabiq, jaanch ke dauran 65 junior colleges ke Fire Safety No Objection Certificates (NOCs) mein gadbad saamne aayi. Fire safety NOC ek aham dastavez hai jo imarat mein aag se bachao aur hifazati intizamaat se mutalliq hota hai.

Taleemi idaron mein fire safety ke qawaid par amal karna zaroori hai, kyun ke colleges mein rozana badi tadaad mein talaba aur staff maujood rehte hain. Aise mein certificates ki tasdeeq, emergency exits, fire extinguishers aur doosre hifazati intizamaat ki jaanch aham hai.

2026–27 Ke Liye 3,241 Junior Colleges Ko Admissions Ki Ijazat

TGBIE se mutalliq report ke mutabiq, academic year 2026–27 ke liye Telangana mein 3,241 junior colleges ko admissions ki ijazat di gayi hai. Pichhle academic year mein yeh tadaad 3,349 batayi gayi thi.

Iske alawa, 12 junior colleges ki applications se mutalliq jaanch ya zaroori documents ki takmeel ka mamla bhi report kiya gaya. In mamlaat mein campus tabdeeli aur dastavez se mutalliq umoor shamil bataye gaye hain.

27 Colleges Mein Zero Admissions Ki Darkhwast

Report ke mutabiq, 27 junior colleges ne zero admissions ke liye darkhwast di. Iska matlab hai ke in colleges ne mutalliq academic year ke liye kisi bhi talib-e-ilm ka dakhla darj na hone ki surat-e-haal report ki.

Colleges ko affiliation aur admissions se mutalliq board ki sharaait poori karna zaroori hota hai. In applications par board ka final faisla official records se hi tasdeeq kiya jana chahiye.

Corporate Colleges Par ₹4 Crore Se Zyada Jurmane Ki Report

TGBIE ki report ke mutabiq, July se October 2026 ke darmiyan mukhtalif khilaf-warziyon par corporate colleges par ₹4 crore se zyada jurmana lagaya gaya.

Is mamle mein college managements ki taraf se qawaid par amal, documents ki jaanch aur board ki manzoori se mutalliq umoor aham hain. Jurmanon ki mukammal tafseelat aur mutalliq idaron ke naam ki tasdeeq official records se ki jani chahiye.

Talaba Aur Walidain Ke Liye Aham Paigham

Fire safety sirf ek rasmi dastavez ka mamla nahi, balkeh talaba aur staff ki jaan ki hifazat se seedha talluq rakhti hai. Walidain aur talaba ko dakhla lene se pehle college ki affiliation aur safety arrangements ke baare mein tasdeeq-shuda maloomat hasil karni chahiye.

• College ki board affiliation aur admission approval check karein.
• Fire extinguishers aur emergency exits ki dastiyabi dekhein.
• Emergency mein bahar nikalne ka rasta maloom karein.
• Fire safety NOC ke baare mein college management se tasdeeq karein.
• Sirf social media ki posts ki bunyaad par kisi college ko farzi ya ghair-mehfooz qarar na dein.

Kya 65 Colleges Ke Naam Jari Hue Hain?

Is khabar ke liye diye gaye matn mein un 65 junior colleges ke naam ki mukammal tasdeeq-shuda fehrist maujood nahi hai. Is liye kisi khaas college ka naam bina official saboot ke dena munasib nahi hoga.

Talaba aur walidain ko chahiye ke TGBIE ya mutalliq fire services authority ki taraf se jari hone wale official notices aur updates ko check karein.

Ahm Note: Is article mein diye gaye numbers aur daaway aapke faraham kiye gaye news draft par mabni hain. Publish karne se pehle 65 colleges, 3,241 admissions approvals aur ₹4 crore se zyada jurmane ki tafseelat ko official source se verify karein. Jaanch mein gadbad ki report ko final legal finding samajhne se pehle official notification dekhein.

Official Updates Kahan Check Karein?

Telangana Board of Intermediate Education:
TGBIE Official Website

Telangana Government:
Official Government Portal

College affiliation, admissions aur fire safety se mutalliq latest notification ke liye official websites par jari notices check karein.

Khulasa

Telangana ke 65 junior colleges ke fire safety certificates mein gadbad ki report ne Intermediate taleemi idaron ke hifazati intizamaat par tawajjoh dilayi hai. Saath hi, 2026–27 admissions approvals, zero admissions ki darkhwaston aur corporate colleges par jurmanon ki tafseelat bhi saamne aayi hain.

Talaba aur walidain ke liye zaroori hai ke college ki affiliation aur safety arrangements ki tasdeeq karein aur kisi bhi khaas idare ke baare mein natija nikalne se pehle official maloomat par bharosa karein.

Keywords: Telangana Education News, TGBIE News 2026, 65 Junior Colleges, Fire Safety NOC, Telangana Intermediate Colleges, College Admissions 2026–27, Hyderabad Education News

Muqeem Tutorial
Telangana Ki Ahm Khabrein Aur Taleemi Updates

 

Telangana 4 Month Employment Scheme 2027: Mazdooron Ke Liye Nayi Khabar

 

Telangana News | Employment

Telangana Mein 4 Mahine Ki Rozgar Scheme Ka Mansuba, Ghareeb Mazdooron Ko Milega Kaam?

Location: Hyderabad, Telangana | Report date: 26 October 2026

Telangana sarkar ne khushk-saali aur El Niño ke mumkin asraat se nipatne ke liye chaar mahine ki khaas rozgar scheme ka mansuba pesh kiya hai. Iska maqsad dehati ilaqon mein rozgar ke mauqe paida karna aur kheti-baari par munhasir mazdooron ko kaam ki sahulat faraham karna hai.

Reports ke mutabiq, yeh scheme January 2027 mein Sankranti ke baad shuru karne aur May 2027 ke aakhir tak chalane ka mansuba hai. Scheme ki final tareekh, registration aur doosri sharaait ki tafseelat ka intezar hai.

Is Khabar Ki Aham Baatein

• Chaar mahine ki khaas rozgar scheme ka mansuba.
• January 2027 mein Sankranti ke baad shuru hone ki tajweez.
• May 2027 ke aakhir tak chalane ka mumkin schedule.
• Maqsad: dehati mazdooron ko kaam aur aamdani ka sahara dena.
• Mazdoori, eligibility aur registration ki final tafseelat abhi tasdeeq talab hain.

El Niño Aur Khushk-Saali Ke Khatre Ke Pesh-e-Nazar Faisla

Telangana mein pani ki kami aur kam baarish ke mumkin asraat ko dekhte hue hukoomat dehati rozgar par tawajjoh de rahi hai. Agar kheti-baari ke kaam mutasir hote hain to rozana mazdoori karne wale afrad ko aamdani ke masail ka saamna karna pad sakta hai.

Chief Minister A. Revanth Reddy ki taraf se bataye gaye mansube ke mutabiq, mushkil halaat mein ghareeb mazdooron ke liye rozgar ke mauqe paida karne par ghour kiya ja raha hai. Pani ke zakhair, agricultural pump sets aur irrigation projects ki surat-e-haal bhi aham hai.

Scheme Ke Tehat Kis Tarah Ke Kaam Honge?

Dehati ilaqon mein zaroori taraqqiyati aur public works ke zariye rozgar dene par tawajjoh di ja sakti hai. Mumkin kaamon mein shamil hain:

• Kheton tak jane wale raaston ki marammat.
• Nalon aur irrigation channels ki safai aur marammat.
• Talabon aur pani ke chhote zakhiron ki bahali.
• Gaon ki zaroori bunyadi sahulaton se mutalliq kaam.

Yeh kaam mumkin misaalein hain. Scheme ke tehat asal mein kaun se kaam karwaye jayenge, yeh official guidelines jari hone ke baad hi wazeh hoga.

Mazdoori Kitni Milegi Aur Kaun Hoga Haqdaar?

Mazdooron ke liye sabse aham sawal rozana mazdoori, eligibility aur registration ka hai. Filhaal dastiyab report mein in tamam mamlaat ki mukammal tasdeeq-shuda tafseelat maujood nahi hain.

• Rozana mazdoori ki raqam abhi tasdeeq talab hai.
• Scheme ke liye eligibility ki sharaait ka intezar hai.
• Registration ki tareekh aur jagah ka official elan zaroori hai.
• Aadhaar card ya job card ki zaroorat hogi ya nahi, yeh wazeh nahi.
• Har district mein rozgar ke mauqon ki tadaad abhi maloom nahi.

MGNREGA Ke Saath Kya Talluq Hoga?

Reports ke mutabiq, Telangana sarkar markazi hukoomat ki National Rural Employment Guarantee Scheme (MGNREGA) ke funds ke ilawa apne funds istemal karke bhi dehati rozgar ke mauqe paida karne par ghour kar rahi hai.

Nayi scheme aur MGNREGA ke darmiyan amli talluq, funding aur mazdooron ke registration ki tafseelat official guidelines se hi wazeh hongi.

Kagaznagar Aur Kumuram Bheem Asifabad Ke Mazdooron Ke Liye Ahm Khabar

Kagaznagar aur Kumuram Bheem Asifabad district ke dehati mazdoor bhi is scheme ki tafseelat par nazar rakhein. Scheme shuru hone aur registration ke mutalliq maloomat ke liye apne Gram Panchayat ya Mandal Parishad Development Officer (MPDO) ke daftar se rabta kiya ja sakta hai.

Mazdooron ko chahiye ke registration ke naam par ghair-mutalliq afrad ko paise na dein aur sirf official sarkari maloomat par bharosa karein.

Hukoomat Ki Mazeed Tayyariyan

El Niño aur pani ki kami ke mumkin asraat se nipatne ke liye dehati ilaqon mein pani ki dastiyabi, kheti-baari aur maveshiyon ke liye charay jaise masail aham ho sakte hain. Scheme ke amli khake aur doosre iqdamat ki tasdeeq official announcements se ki jani chahiye.

Khulasa

Telangana sarkar January 2027 mein Sankranti ke baad se May ke aakhir tak chaar mahine ki khaas rozgar scheme chalane ke mansube par ghour kar rahi hai. Iska bunyadi maqsad khushk-saali aur kheti-baari mein mumkin susti ke dauran dehati mazdooron ko kaam dena hai.

Ahm Note: Scheme ki final tareekh, mazdoori, eligibility aur registration ka tareeqa official guidelines jari hone ke baad hi tasdeeq-shuda samjha jayega. Is article mein scheme ko mansube ke taur par bayan kiya gaya hai, na ke final notification ke taur par.

Source: The New Indian Express — Telangana News

Official updates ke liye: Telangana Government Portal

Keywords: Telangana Employment Scheme 2027, Telangana Rozgar Scheme, 4 Month Job Scheme, Telangana Mazdoor News, Kagaznagar News, Kumuram Bheem Asifabad News, Telangana Government Schemes

Muqeem Tutorial — Telangana Ki Ahm Khabrein Aur Taleemi Updates

TS Class 10 Physics Official Model Question Paper 2 with Solved Answers - Part-B

📋 Official Board Practice Series — Model Paper 2

TS SSC Physics Official Model Question Paper 2

Complete Solved 40-Mark Board Paper: Section I (2M Very Short), Section II (4M Short & Numericals), Section III (6M Essay Questions), Optics Diagrams & Part-B Objective MCQs

📌 Model Paper 2 Blueprint & Marks Allocation

1. Section I — Very Short (2M Each)

6 Direct Questions covering essential definitions, concepts, and unit conversions:

3 Questions Physics + 3 Questions Chemistry = 12 Marks

2. Section II — Short & Numericals (4M Each)

4 Problem-solving and procedural questions with step-by-step calculations:

2 Physics Numericals + 2 Chemistry Processes = 16 Marks

3. Section III — Essay & Choice (6M Each)

2 High-weightage essay questions with internal choice, ray diagrams, and experiments:

1 Physics Essay + 1 Chemistry Essay = 12 Marks

📊 Key High-Weightage Topics Covered in Model Paper 2

Targeted core concepts curated according to the latest SCERT Telangana Board Examination Pattern:

High Priority Chapters in Model Paper 2

1. Total Internal Reflection & Lenses

Focus: Critical angle formula n = 1/sin(C), lens magnification m = v/u, and optical fibers.

2. Series Resistors & Power Bill

Focus: Series circuit calculations, potential drops, and kWh monthly power energy bill calculations.

3. Acids, Bases & Quantum Numbers

Focus: pH scale in stomach/teeth and 4 quantum numbers for 4s¹ electron of Potassium (K, Z = 19).

4. Periodic Table & Organic Chemistry

Focus: Periodic trends (Atomic size, IE, EN) across periods/groups and Saponification reaction.

Valuation Tip: Write proper units (Tesla, Weber, Ohm, Volt, Watt), draw clean ray diagrams with arrows, and state balanced chemical equations with state symbols to score full marks.

📝 Section I: Very Short Answer Questions (2 Marks Each)

QUESTION 1 - 2 MARKS (PHYSICS)

Q1. Define Critical Angle and Total Internal Reflection. Write the formula connecting Critical Angle (C) and Refractive Index (n).

Answer:

• Critical Angle (C): The angle of incidence in a denser medium for which the angle of refraction in the rarer medium becomes exactly 90°.
• Total Internal Reflection: When light travels from a denser to a rarer medium at an angle of incidence greater than the critical angle, the entire light reflects back into the denser medium.
• Formula: n = 1 / sin(C)   or   sin(C) = 1 / n

QUESTION 2 - 2 MARKS (PHYSICS)

Q2. Calculate the focal length of a lens having a power of -2.5 D. What type of lens is it?

Given: Power P = -2.5 D

Formula: Focal length f = 100 / P (in cm)

f = 100 / (-2.5) = -40 cm

✓ Final Answer: Focal length f = -40 cm. Negative sign indicates it is a Concave Lens (Diverging Lens).

QUESTION 3 - 2 MARKS (PHYSICS)

Q3. State Faraday's Law of Electromagnetic Induction.

Answer:

• Faraday's Law: Whenever there is a continuous change in the magnetic flux linked with a closed coil, an induced electromotive force (EMF) and current are produced in the coil.
• The magnitude of the induced EMF is directly proportional to the rate of change of magnetic flux linked with the circuit:
  ε = - ΔΦ / Δt

QUESTION 4 - 2 MARKS (CHEMISTRY)

Q4. Write the set of four Quantum Numbers for the 17th electron of Chlorine (Cl, Z = 17).

Answer:

• Chlorine (Cl, Z = 17): Configuration = 1s² 2s² 2p⁶ 3s² 3p⁵. The 17th electron enters the 3p subshell.
• 4 Quantum Numbers:
  • Principal Quantum Number (n) = 3
  • Angular Momentum Quantum Number (l) = 1 (p-subshell)
  • Magnetic Quantum Number (m_l) = 0 (or +1 / -1)
  • Spin Quantum Number (m_s) = -½ (paired spin)

QUESTION 5 - 2 MARKS (CHEMISTRY)

Q5. Why does tooth decay start when mouth pH falls below 5.5? How can it be prevented?

Answer:

• Reason: Tooth enamel is made of Calcium Phosphate (hardest substance in the body). When mouth pH drops below 5.5, the acid produced by oral bacteria degrading leftover sugar particles corrodes and dissolves the enamel.
• Prevention: Brushing teeth after meals using alkaline toothpaste neutralizes excess mouth acid and prevents decay.

QUESTION 6 - 2 MARKS (CHEMISTRY)

Q6. What is Saponification? Write the chemical equation for the preparation of soap.

Answer:

• Saponification: The process of hydrolyzing an ester (fat or oil) by heating it with an aqueous strong base like Sodium Hydroxide (NaOH) to prepare Soap.
• Chemical Equation:
  CH₃COOC₂H₅ (Ester) + NaOH → CH₃COONa (Soap) + C₂H₅OH (Alcohol)

🧮 Section II: Short Answer Questions & Solved Numericals (4 Marks Each)

QUESTION 7 - 4 MARKS (PHYSICS NUMERICAL)

Q7. Three resistors of 10 Ω, 20 Ω, and 30 Ω are connected in series across a 12 V battery. Calculate:
(a) Equivalent resistance of the series circuit.
(b) Total current flowing through the circuit.
(c) Potential difference (voltage drop) across the 10 Ω resistor.

Given Data: R₁ = 10 Ω, R₂ = 20 Ω, R₃ = 30 Ω, Voltage V = 12 V

(a) Calculating Equivalent Resistance (R_eq) in Series:

R_eq = R₁ + R₂ + R₃ = 10 + 20 + 30 = 60 Ω

(b) Calculating Total Circuit Current (I):

I = V / R_eq = 12 V / 60 Ω = 0.2 A

(c) Calculating Voltage Drop across 10 Ω Resistor (V₁):

V₁ = I × R₁ = 0.2 A × 10 Ω = 2 V

✓ Final Result:
1. Equivalent Resistance R_eq = 60 Ω.
2. Total Circuit Current I = 0.2 A.
3. Potential Difference across 10 Ω = 2 V.

QUESTION 8 - 4 MARKS (PHYSICS OPTICS NUMERICAL)

Q8. A convex lens forms a real inverted image at a distance of 30 cm from the lens for an object placed at a distance of 15 cm in front of it. Calculate:
(a) Focal length of the lens (f).
(b) Magnification (m) produced by the lens.

Given Data (Sign Convention): Object distance u = -15 cm | Image distance v = +30 cm (Real image)

(a) Calculating Focal Length (f) using Lens Formula (1/f = 1/v - 1/u):

1 / f = 1 / 30 - 1 / (-15) = 1 / 30 + 1 / 15 = (1 + 2) / 30 = 3 / 30 = 1 / 10

f = +10 cm

(b) Calculating Magnification (m):

m = v / u = (+30) / (-15) = -2

✓ Final Answer:
1. Focal Length f = +10 cm (Convex Lens).
2. Magnification m = -2 (Image is real, inverted, and magnified 2 times).

QUESTION 9 - 4 MARKS (CHEMISTRY)

Q9. Describe the Froth Floatation process for concentrating sulphide ores with a neat principle and process explanation.

Answer:

• Principle: Based on the difference in wetting properties of ore particles and gangue impurities. Ore particles are preferentially wetted by pine oil, while gangue particles are wetted by water.
• Operational Procedure:
  1. Finely crushed sulphide ore (e.g., Galena PbS or Zinc Blende ZnS) is mixed with water and pine oil in a large flotation tank.
  2. Compressed air is blown through a pipe to agitate the mixture and generate rich froth.
  3. Light sulphide ore particles adhere to pine oil bubbles and float to the surface as froth, which is skimmed off and dried. Heavy gangue settles at the bottom.

QUESTION 10 - 4 MARKS (CHEMISTRY)

Q10. Write the IUPAC names, structural formulas, and functional groups for the following organic compounds:
(a) CH₃CH₂OH
(b) CH₃COOH
(c) CH₃COCH₃
(d) CH₃CHO

Formula	Functional Group	IUPAC Name	Common Name
CH3CH2OH	Alcohol (−OH)	Ethanol	Ethyl Alcohol
CH3COOH	Carboxylic Acid (−COOH)	Ethanoic Acid	Acetic Acid
CH3COCH3	Ketone (>C=O)	Propanone	Acetone
CH3CHO	Aldehyde (−CHO)	Ethanal	Acetaldehyde

📑 Section III: Essay Type Questions & Ray Diagrams (6 Marks Each)

QUESTION 11 (A) - 6 MARKS (PHYSICS ESSAY)

Q11 (A). An object is placed at 2F₁ (Center of Curvature) in front of a Convex Lens. Describe the position, nature, size, and magnification of the image formed. Draw a schematic ray diagram.

Answer:

• Position of Object: At 2F₁ in front of the convex lens.
• Position of Image: Formed exactly at 2F₂ on the opposite side of the lens.
• Nature and Characteristics of Image:
  1. Nature: Real and Inverted.
  2. Size: Same size as the object.
  3. Magnification (m): m = -1 (Negative sign indicates inverted image).

Ray Tracing Rules Used:

1. Ray 1: Parallel to principal axis refracts through focus F₂.

2. Ray 2: Passing through Optic Center O continues straight undeviated.

3. Intersection Point: Both refracted rays intersect at 2F₂ to form the real inverted image.

QUESTION 11 (B) - 6 MARKS (ALTERNATIVE ESSAY)

Q11 (B). Explain the defect of vision Myopia (Nearsightedness). State its causes and explain how it can be corrected using a Concave Lens with a formula for focal length.

Answer:

• Myopia: A defect of vision in which a person can see nearby objects clearly, but cannot see distant objects distinctly because the image of a distant object forms in front of the retina rather than on it.
• Causes of Myopia:
  1. Elongation of the eyeball from front to back.
  2. Excessive curvature of the eye lens (focal length becomes too short).
• Correction using Concave Lens: A concave lens of suitable focal length diverges parallel light rays coming from a distant object so that they appear to diverge from the eye's far point (D) and focus precisely on the retina.
• Focal Length Formula:
  f = -D (where D is the distance of the far point of the myopic eye).

QUESTION 12 - 6 MARKS (CHEMISTRY ESSAY)

Q12. Explain the trends of Atomic Radius, Ionization Energy, and Electronegativity across a Period (Left to Right) and down a Group (Top to Bottom) in the Modern Periodic Table with justifications.

Answer:

Periodic Property	Across a Period (Left to Right)	Down a Group (Top to Bottom)
1. Atomic Radius	Decreases: Nuclear charge increases while principal energy shell remains constant, pulling valence electrons tighter toward the nucleus.	Increases: New principal energy shells are added at each successive step, expanding atomic size.
2. Ionization Energy (IE)	Increases: Smaller atomic radius increases the electrostatic nuclear attraction on valence electrons, requiring higher energy to remove an electron.	Decreases: Outer electrons are farther from the nucleus and shielded by inner shell electrons, making them easier to remove.
3. Electronegativity (EN)	Increases: Stronger nuclear pull enhances the ability to attract shared electron pairs in a covalent bond (Fluorine EN = 4.0).	Decreases: Larger atomic size weakens nuclear attraction on bonded electron pairs.

🎯 PART-B Objective Bits Bank (10 MCQs - Model Paper 2)

BIT 1

1. The focal length of a concave lens is -20 cm. Its power in dioptres is:

• -5.0 D
• +5.0 D
• -2.0 D
• +0.2 D

✓ Correct Option: A (P = 100 / f = 100 / -20 = -5.0 D)

BIT 2

2. What ray passes undeviated through a lens?

• Ray parallel to principal axis
• Ray passing through Optic Center (O)
• Ray passing through Focus (F)
• Ray at 45° angle

✓ Correct Option: B (Ray passing through Optic Center)

BIT 3

3. What is the SI unit of Magnetic Flux (Φ)?

• Tesla
• Weber
• Ohm
• Volt

✓ Correct Option: B (Weber - Wb)

BIT 4

4. Fleming's Right Hand Rule determines the direction of:

• Magnetic Force
• Induced Current
• Electric Field
• Resistance

✓ Correct Option: B (Induced Current in a Generator)

BIT 5

5. Maximum electron capacity of a d-subshell is:

• 2
• 6
• 10
• 14

✓ Correct Option: C (10 electrons)

BIT 6

6. Tooth decay begins when mouth pH drops below:

• 7.0
• 6.5
• 5.5
• 4.0

✓ Correct Option: C (pH below 5.5)

BIT 7

7. What is the chemical formula of Cinnabar (ore of Mercury)?

• HgO
• HgS
• PbS
• ZnS

✓ Correct Option: B (HgS)

BIT 8

8. Modern Periodic Law states that properties of elements are periodic functions of their:

• Atomic mass
• Atomic number
• Mass number
• Valency

✓ Correct Option: B (Atomic Number)

BIT 9

9. General formula of Alkyne hydrocarbons containing a triple bond is:

• C_nH_2n+2
• C_nH_2n
• C_nH_2n-2
• C_nH_2n+1

✓ Correct Option: C (C_nH_2n-2)

BIT 10

10. The functional group present in Propanone (Acetone) is:

• Alcohol (−OH)
• Aldehyde (−CHO)
• Ketone (>C=O)
• Carboxylic Acid (−COOH)

✓ Correct Option: C (Ketone >C=O)

TS Class 10 Physics Official Model Question Paper 1 with Solved Answers - & Part-B MCQs

📋 Official Board Practice Series — Model Paper 1

TS SSC Physics Official Model Question Paper 1

Complete Solved 40-Mark Board Paper: Section I (2M Very Short), Section II (4M Short & Numericals), Section III (6M Essay Questions), Optics Diagrams & Part-B Objective MCQs

📌 Model Paper 1 Blueprint & Marks Allocation

1. Section I — Very Short (2M Each)

6 Direct Questions covering essential definitions, concepts, and unit conversions:

3 Questions Physics + 3 Questions Chemistry = 12 Marks

2. Section II — Short & Numericals (4M Each)

4 Problem-solving and procedural questions with step-by-step calculations:

2 Physics Numericals + 2 Chemistry Processes = 16 Marks

3. Section III — Essay & Choice (6M Each)

2 High-weightage essay questions with internal choice, ray diagrams, and experiments:

1 Physics Essay + 1 Chemistry Essay = 12 Marks

📊 Key High-Weightage Topics Covered in Model Paper 1

Targeted core concepts curated according to the latest SCERT Telangana Board Examination Pattern:

High Priority Chapters in Model Paper 1

1. Refraction & Convex Lenses

Focus: Snell's law, focal length calculations, and ray diagrams for real vs virtual images.

2. Electric Circuits & Ohm's Law

Focus: Parallel resistor networks, current distribution, and experimental verification of V = IR.

3. Quantum Numbers & Bonding

Focus: Quantum numbers set for 3d electrons and VSEPR molecular geometry of H₂O and NH₃.

4. Metallurgy & Carbon Compounds

Focus: Calcination vs Roasting, Thermite reduction equation, and Esterification mechanism.

Valuation Tip: Write proper units (Tesla, Weber, Ohm, Volt, Watt), draw clean ray diagrams with arrows, and state balanced chemical equations with state symbols to score full marks.

📝 Section I: Very Short Answer Questions (2 Marks Each)

QUESTION 1 - 2 MARKS (PHYSICS)

Q1. State Snell's Law of Refraction and write its mathematical formula.

Answer:

• Snell's Law: The ratio of the sine of the angle of incidence (i) to the sine of the angle of refraction (r) is constant for a given pair of media and a given wavelength of light.
• Formula:
  n₁ × sin(i) = n₂ × sin(r)   or   sin(i) / sin(r) = n₂₁
• Where: i = angle of incidence, r = angle of refraction, and n₂₁ = refractive index of second medium relative to first.

QUESTION 2 - 2 MARKS (PHYSICS)

Q2. What is the power of a convex lens of focal length +25 cm?

Given: Focal length f = +25 cm = +0.25 m

Formula: Power P = 100 / f (in cm) = 1 / f (in m)

P = 100 / (+25) = +4.0 D (Dioptres)

✓ Final Answer: Power of the lens = +4.0 D

QUESTION 3 - 2 MARKS (PHYSICS)

Q3. State Right-Hand Thumb Rule for determining the direction of magnetic field lines.

Answer:

• Statement: Imagine holding a straight current-carrying conductor in your right hand such that the stretched thumb points in the direction of the Electric Current.
• Then, your curled fingers wrapped around the conductor point in the direction of the Magnetic Field Lines (concentric circles).

QUESTION 4 - 2 MARKS (CHEMISTRY)

Q4. Write the electronic configuration of Chromium (Cr, Z = 24) and explain why it shows an anomalous configuration.

Answer:

• Electronic Configuration of Cr (Z = 24): 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d⁵ (or [Ar] 4s¹ 3d⁵).
• Reason: Half-filled 3d⁵ subshell provides extra stability due to orbital symmetry and high electron exchange energy compared to expected 4s² 3d⁴.

QUESTION 5 - 2 MARKS (CHEMISTRY)

Q5. Define Catenation. Which element exhibits maximum catenation ability and why?

Answer:

• Catenation: The unique property of an element to form strong covalent bonds with atoms of the same element to construct long straight, branched, or ring-shaped molecular chains.
• Element: Carbon (C) exhibits maximum catenation due to its small atomic radius and very high Carbon-Carbon (C−C) single bond energy (347 kJ/mol).

QUESTION 6 - 2 MARKS (CHEMISTRY)

Q6. Write the chemical formula of Bauxite and Galena.

Answer:

• Bauxite (Ore of Aluminium): Al₂O₃ · 2H₂O
• Galena (Ore of Lead): PbS

🧮 Section II: Short Answer Questions & Solved Numericals (4 Marks Each)

QUESTION 7 - 4 MARKS (PHYSICS NUMERICAL)

Q7. Two resistors of 6 Ω and 12 Ω are connected in parallel across a 12 V battery. Calculate:
(a) Equivalent resistance of the parallel combination.
(b) Total current supplied by the battery.
(c) Current passing through the 6 Ω resistor.

Given Data: R₁ = 6 Ω, R₂ = 12 Ω, Battery Voltage V = 12 V

(a) Calculating Equivalent Resistance (R_eq):

1 / R_eq = 1 / R₁ + 1 / R₂ = 1 / 6 + 1 / 12 = (2 + 1) / 12 = 3 / 12 = 1 / 4

R_eq = 4 Ω

(b) Calculating Total Current (I):

I = V / R_eq = 12 V / 4 Ω = 3 A

(c) Calculating Current through 6 Ω Resistor (I₁):

I₁ = V / R₁ = 12 V / 6 Ω = 2 A

✓ Final Result:
1. Equivalent Resistance R_eq = 4 Ω.
2. Total Circuit Current I = 3 A.
3. Branch Current through 6 Ω = 2 A.

QUESTION 8 - 4 MARKS (PHYSICS OPTICS NUMERICAL)

Q8. Speed of light in vacuum is 3 × 10⁸ m/s. Calculate the speed of light in a glass block whose refractive index is 1.5.

Given: Speed of light in vacuum c = 3 × 10⁸ m/s

Refractive index of glass n = 1.5

Formula: n = c / v ⇒ v = c / n

v = (3 × 10⁸ m/s) / 1.5 = 2 × 10⁸ m/s

✓ Final Answer: Speed of light in glass = 2 × 10⁸ m/s.

QUESTION 9 - 4 MARKS (CHEMISTRY)

Q9. Differentiate between Calcination and Roasting with balanced chemical equations.

Feature	Calcination	Roasting
Presence of Air	Heating ore in absence or limited supply of air.	Heating ore strongly in excess supply of air.
Ore Type	Used mainly for Carbonate and Hydrated Ores.	Used specifically for Sulphide Ores.
Gas Evolved	Carbon Dioxide (CO2) gas is driven off.	Sulfur Dioxide (SO2) gas is evolved.
Reaction Example	ZnCO3(s) →Δ→ ZnO(s) + CO2(g)↑	2ZnS(s) + 3O2(g) →Δ→ 2ZnO(s) + 2SO2(g)↑

QUESTION 10 - 4 MARKS (CHEMISTRY)

Q10. Explain Esterification Reaction with a balanced chemical equation and state two uses of esters.

Answer:

• Esterification: The chemical reaction in which a Carboxylic acid reacts with an Alcohol in the presence of concentrated Sulfuric acid (H₂SO₄) catalyst to form a sweet fruity-smelling compound called an Ester.
• Chemical Equation:
  CH₃COOH (Ethanoic Acid) + C₂H₅OH (Ethanol) →conc. H₂SO₄→ CH₃COOC₂H₅ (Ethyl Acetate) + H₂O
• Uses:
  1. Used in making synthetic perfumes and cosmetics.
  2. Used as artificial fruity flavoring agents in food products and ice creams.

📑 Section III: Essay Type Questions & Ray Diagrams (6 Marks Each)

QUESTION 11 (A) - 6 MARKS (PHYSICS ESSAY)

Q11 (A). An object is placed between F₁ and 2F₁ of a Convex Lens. Describe the position, nature, size, and magnification of the image formed. Draw a schematic ray diagram.

Answer:

• Position of Object: Between Focus (F₁) and Center of Curvature (2F₁).
• Position of Image: Formed beyond 2F₂ on the opposite side of the lens.
• Nature and Characteristics of Image:
  1. Nature: Real and Inverted.
  2. Size: Magnified (Larger than object size).
  3. Magnification (m): Negative and magnitude greater than 1 (|m| > 1).

Ray Tracing Procedure:

1. Ray 1: Parallel to principal axis refracts through focus F₂.

2. Ray 2: Passing through optic center O continues straight without deviation.

3. Both refracted rays intersect beyond 2F₂ to construct the real inverted image.

QUESTION 11 (B) - 6 MARKS (ALTERNATIVE ESSAY)

Q11 (B). Describe Oersted's Experiment to demonstrate that an electric current produces a magnetic field around a conductor.

Answer:

• Aim: To prove experimentally that an electric current flowing through a conductor creates a magnetic field around it.
• Apparatus: Straight copper wire, magnetic compass needle, battery, switch key, and connecting wires.
• Procedure:
  1. Place a long copper wire parallel to and directly above a magnetic compass needle aligned in the North-South direction.
  2. Connect the wire to a battery through a plug key.
  3. Close the key so current flows from South to North. Observe compass deflection.
  4. Reverse battery terminals so current flows from North to South. Observe deflection again.
• Observation:
  • Current from South to North: Compass North pole deflects towards West.
  • Current from North to South: Compass North pole deflects towards East.
• Conclusion: Deflection of magnetic needle confirms the generation of a magnetic field around a current-carrying wire.

QUESTION 12 - 6 MARKS (CHEMISTRY ESSAY)

Q12. Describe VSEPR Theory principles and explain the 3D molecular shape and bond angles of Methane (CH₄), Ammonia (NH₃), and Water (H₂O).

Answer:

Molecule	Bond Pairs (BP)	Lone Pairs (LP)	3D Molecular Shape	Bond Angle
Methane (CH4)	4 Bond Pairs	0 Lone Pairs	Tetrahedral	109°28'
Ammonia (NH3)	3 Bond Pairs	1 Lone Pair	Trigonal Pyramidal	107°
Water (H2O)	2 Bond Pairs	2 Lone Pairs	Bent / V-Shaped	104°30'

Key Explanation: Repulsion hierarchy: (LP-LP) > (LP-BP) > (BP-BP). Unpaired lone pairs push bonding electron pairs closer, reducing bond angles below the ideal 109°28' tetrahedral angle.

🎯 PART-B Objective Bits Bank (10 MCQs - Model Paper 1)

BIT 1

1. The SI unit of Refractive Index is:

• m/s
• Dioptre
• Weber
• No unit (dimensionless)

✓ Correct Option: D (No unit - ratio of speeds)

BIT 2

2. What focal length lens is required to achieve a power of +5.0 D?

• +20 cm
• +50 cm
• +10 cm
• -20 cm

✓ Correct Option: A (f = 100 / P = 100 / 5 = +20 cm)

BIT 3

3. Commercial unit of electrical energy 1 kWh is equal to:

• 3.6 × 10⁵ J
• 3.6 × 10⁶ J
• 1000 J
• 3600 J

✓ Correct Option: B (3.6 × 10⁶ Joules)

BIT 4

4. Fleming's Left Hand Rule is applied to determine motion in an:

• AC Generator
• Electric Motor
• Transformer
• Galvanometer

✓ Correct Option: B (Electric Motor)

BIT 5

5. Which halogen is the most electronegative element in the periodic table?

• Chlorine
• Fluorine
• Bromine
• Iodine

✓ Correct Option: B (Fluorine - F)

BIT 6

6. Ground state electronic configuration of Copper (Cu, Z = 29) is:

• [Ar] 4s² 3d⁹
• [Ar] 4s¹ 3d¹⁰
• [Ar] 4s² 3d¹⁰
• [Ar] 4s⁰ 3d¹⁰

✓ Correct Option: B ([Ar] 4s¹ 3d¹⁰)

BIT 7

7. What is the ore of Lead (Pb)?

• Bauxite
• Galena (PbS)
• Hematite
• Cinnabar

✓ Correct Option: B (Galena - PbS)

BIT 8

8. Thermite process uses which metal powder as a reducing agent?

• Copper
• Aluminium
• Zinc
• Magnesium

✓ Correct Option: B (Aluminium powder)

BIT 9

9. General formula of Alkene hydrocarbons containing a double bond is:

• C_nH_2n+2
• C_nH_2n
• C_nH_2n-2
• C_nH_2n+1

✓ Correct Option: B (C_nH_2n)

BIT 10

10. IUPAC suffix for Carboxylic Acids is:

• -al
• -ol
• -one
• -oic acid

✓ Correct Option: D (-oic acid)

TS Class 10 Physical Science Solved Public Exam Paper 2025 - Physics & Chemistry Solutions, & Part-B

📄 Official Board Exam Solution — 2025

TS SSC Physical Science 2025 Public Exam Solved Paper

Complete Step-by-Step Official Solutions: Physics & Chemistry Sections, Refraction at Curved Surfaces, Circuit Power Numericals & Part-B Objective MCQs

📌 2025 Board Examination Pattern & Weightage Summary

1. Total Weightage & Time

Total Marks: 40 Marks (Part-A: 35 Marks + Part-B: 5 Marks) | Duration: 1 Hour 30 Minutes

Part-A = 35 Marks  |  Part-B = 5 Marks (10 MCQs)

2. Physics Section Focus

Vision Defects (Myopia/Hypermetropia), Convex Lens Ray Diagrams, Electric Power & Electromagnetism:

Physics Section = 20 Marks

3. Chemistry Section Focus

Acid-Base Neutralization, Quantum Numbers, Periodic Trends & Organic Reactions (Esterification):

Chemistry Section = 20 Marks

📊 TS SSC 2025 Question Paper Key Topics Analysis

High-priority topics that appeared in the official 2025 Telangana Class 10 Public Examination:

Key Core Topics in 2025 Paper

1. Defects of Vision & Lens Correction

Featured Question: Myopia vs Hypermetropia, focal length calculation, and corrective concave/convex lens power.

2. Resistors in Parallel & Power Bill

Featured Question: Solved 3-resistor parallel circuit numerical and monthly kWh electrical energy cost calculation.

3. Quantum Numbers & Bonding

Featured Question: Complete set of 4 quantum numbers for the 11th electron of Sodium (Na, Z = 11) & Lewis dot structures.

4. Acids, Bases & Carbon Compounds

Featured Question: pH importance in everyday life, Esterification, and Saponification reaction equations.

Official Board Pattern Note: All answers are strictly grounded in TS SCERT Class 10 Physical Science textbook standards and verified according to official board valuation guidelines.

⚡ Physics Section Solved Questions (Part-A)

PHYSICS - 2 MARKS

Q1. Differentiate between Myopia (Nearsightedness) and Hypermetropia (Farsightedness). Name the type of lens used to correct each defect.

Feature	Myopia (Nearsightedness)	Hypermetropia (Farsightedness)
Vision Capability	Can see nearby objects clearly, but cannot see distant objects distinctly.	Can see distant objects clearly, but cannot see nearby objects distinctly.
Image Formation	Image of distant object forms in front of the retina.	Image of nearby object forms behind the retina.
Cause of Defect	Elongation of eyeball or excessive curvature of eye lens.	Shortening of eyeball or focal length of eye lens being too long.
Corrective Lens Required	Concave Lens (Diverging lens of suitable power).	Convex Lens (Converging lens of suitable power).

PHYSICS - 4 MARKS SOLVED NUMERICAL

Q2. Three resistors of 20 Ω, 30 Ω, and 60 Ω are connected in parallel across a 12 V battery. Calculate:
(a) Equivalent resistance of the parallel combination.
(b) Total current drawn from the battery.
(c) Current flowing through the 20 Ω resistor.

Given Data: R₁ = 20 Ω, R₂ = 30 Ω, R₃ = 60 Ω, Battery Voltage V = 12 V

(a) Calculating Equivalent Resistance (R_eq):

1 / R_eq = 1 / R₁ + 1 / R₂ + 1 / R₃

1 / R_eq = 1 / 20 + 1 / 30 + 1 / 60 = (3 + 2 + 1) / 60 = 6 / 60 = 1 / 10

R_eq = 10 Ω

(b) Calculating Total Circuit Current (I):

I = V / R_eq = 12 V / 10 Ω = 1.2 A

(c) Calculating Current through 20 Ω Resistor (I₁):

I₁ = V / R₁ = 12 V / 20 Ω = 0.6 A

✓ Final Answer:
1. Equivalent Resistance R_eq = 10 Ω.
2. Total Circuit Current I = 1.2 A.
3. Branch Current I₁ (20 Ω) = 0.6 A.

PHYSICS - 6 MARKS ESSAY & RAY DIAGRAM

Q3. An object is placed beyond 2F₁ (Center of Curvature) in front of a Convex Lens. Describe the position, nature, size, and magnification of the image formed. Draw a neat schematic ray diagram.

Answer:

• Position of Object: Beyond 2F₁ in front of the convex lens.
• Position of Image: Formed between F₂ and 2F₂ on the opposite side of the lens.
• Nature and Characteristics of Image:
  1. Nature: Real and Inverted.
  2. Size: Diminished (Smaller than the object).
  3. Magnification (m): Negative and less than 1 (|m| < 1).

Ray Tracing Rules Used:

1. Ray 1: Parallel to principal axis passes through focus F₂ after refraction.

2. Ray 2: Passing through Optic Center O continues straight undeviated.

3. Intersection Point: Both refracted rays meet between F₂ and 2F₂ to form a real inverted diminished image.

🧪 Chemistry Section Solved Questions (Part-A)

CHEMISTRY - 2 MARKS

Q4. Explain the importance of pH in everyday life with respect to:
(a) Human digestive system.
(b) Tooth decay prevention.

Answer:

• (a) Human Digestive System: Stomach produces Hydrochloric Acid (HCl, pH ~ 1.5 to 3.5) to digest food without harming stomach walls. Excess acid during indigestion causes pain, which is neutralized by taking Antacids (mild bases like Mg(OH)₂ Milk of Magnesia).
• (b) Tooth Decay Prevention: Tooth decay starts when mouth pH falls below 5.5. Bacteria in the mouth produce acids by degrading sugar particles left in teeth. Using alkaline toothpaste neutralizes the excess acid and prevents enamel decay.

CHEMISTRY - 4 MARKS

Q5. Write the set of four Quantum Numbers for the 11th electron of Sodium (Na, Z = 11) and the 19th electron of Potassium (K, Z = 19).

Element & Atomic No.	Outermost Orbital	n	l	ml	ms
Sodium (Na, Z = 11)	3s1 subshell	3	0 (s)	0	+½
Potassium (K, Z = 19)	4s1 subshell	4	0 (s)	0	+½

CHEMISTRY - 6 MARKS ESSAY

Q6. Explain the following organic reactions with balanced chemical equations:
(a) Esterification Reaction.
(b) Saponification Reaction.
(c) Oxidation of Ethanol using Alkaline KMnO₄.

(a) Esterification Reaction:

Reaction between Ethanoic acid and Ethanol in the presence of conc. H₂SO₄ to form sweet-smelling Ethyl acetate ester:

CH₃COOH + C₂H₅OH →conc. H₂SO₄→ CH₃COOC₂H₅ + H₂O

(b) Saponification Reaction:

Reaction of an ester with aqueous Sodium Hydroxide (NaOH) to prepare Soap:

CH₃COOC₂H₅ + NaOH → CH₃COONa (Soap) + C₂H₅OH

(c) Oxidation of Ethanol:

Ethanol is oxidized to Ethanoic acid on heating with Alkaline Potassium Permanganate (Alk. KMnO₄):

CH₃CH₂OH + 2[O] →Alk. KMnO₄ + Heat→ CH₃COOH + H₂O

✓ These three chemical reactions form the core organic chemistry equations in Class 10 Board Exams.

🎯 PART-B Objective Bits Bank (10 MCQs - Official 2025 Paper)

BIT 1

1. The power of a lens used to correct Myopia is always:

• Positive (+)
• Negative (-)
• Zero
• Infinite

✓ Correct Option: B (Negative - Concave lens)

BIT 2

2. What is the least distance of distinct vision for a normal human adult eye?

• 2.5 cm
• 25 cm
• 2.5 m
• Infinity

✓ Correct Option: B (25 cm)

BIT 3

3. What is the SI unit of Electric Power?

• Joule
• Watt
• Ampere
• Ohm-meter

✓ Correct Option: B (Watt - W)

BIT 4

4. An AC Generator converts mechanical energy into electrical energy using:

• Split rings
• Slip rings
• Commutator
• Carbon brushes only

✓ Correct Option: B (Slip rings)

BIT 5

5. What is the maximum number of electrons that can occupy a d-subshell?

• 2
• 6
• 10
• 14

✓ Correct Option: C (10 electrons)

BIT 6

6. Tooth decay begins when mouth pH drops below:

• 7.0
• 6.5
• 5.5
• 4.0

✓ Correct Option: C (pH below 5.5)

BIT 7

7. Bauxite ore is concentrated using which method?

• Froth Floatation
• Leaching / Chemical Method
• Magnetic Separation
• Roasting

✓ Correct Option: B (Leaching / Chemical Method)

BIT 8

8. Modern Periodic Law states that properties of elements are periodic functions of their:

• Atomic mass
• Atomic number
• Mass number
• Density

✓ Correct Option: B (Atomic number - Henry Moseley)

BIT 9

9. Chemical formula of Ethyl Ethanoate ester is:

• CH₃COOH
• CH₃COOC₂H₅
• C₂H₅OH
• CH₃CHO

✓ Correct Option: B (CH₃COOC₂H₅)

BIT 10

10. The functional group present in Alcohols is:

• -CHO
• -OH
• -COOH
• >C=O

✓ Correct Option: B (-OH)